一则PHP面试题

博主：hoping
发布时间： 2020-09-12 03:28:03
86

![](https://img.imzhp.com/19/images/80fc41e9d98493da579c59715dbc42d7.jpg-web)
直接上代码吧：
```php
<?php
if($argc>1){
    if(function_exists($argv[1])) {
        $tmp = $argv;
        array_shift($tmp);
        array_shift($tmp);
        call_user_func_array($argv[1], $tmp);
        exit;
    }
}
echo 'php ' . basename(__FILE__) . ' <funcname> <arg1> <arg2>' . PHP_EOL;
echo '  funcname: jiujiu, rmb, chefei, findsecnum' . PHP_EOL;

//99乘法表
function jiujiu(){
    for($i=9;$i>0;$i--){
        for($j=9;$j>=$i;$j--){
            echo $j . '*' . $i . '=' . ($i*$j) . ' ';
        }
        echo PHP_EOL;
    }
}

/**
 * 人民币解析
 */
function rmb($num = 123.22) {
    $rmb = [
        '10000' => '100元',
        '5000' => '50元',
        '2000' => '20元',
        '1000' => '10元',
        '500' => '5元',
        '100' => '1元',
        '50' => '5毛',
        '10' => '1毛',
        '5' => '5分',
        '1' => '1分'
    ];
    $str = '';
    $num = $num * 100;
    foreach($rmb as $k => $v) {
        if($num>$k) {
            $c = intval($num/$k);
            $str .= $v . $c . '张';
            $num-=$c*$k;
        }
        if(!$num) break;
    }
    echo $str . PHP_EOL;

}

function CheFei($start = '香港', $end = '虎门') {
    if(is_array($start)) {
        list($start, $end) = $start;
    }

$chepiao = [
        [
            'start' => '深圳',
            'end' => '广州',
            'money' => '60'
        ],
        [
            'start' => '广州',
            'end' => '虎门',
            'money' => '50'
        ],
        [
            'start' => '虎门',
            'end' => '中山',
            'money' => '40'
        ],
        [
            'start' => '中山',
            'end' => '珠海',
            'money' => '36'
        ],
        [
            'start' => '珠海',
            'end' => '澳门',
            'money' => '34'
        ],
        [
            'start' => '澳门',
            'end' => '香港',
            'money' => '89'
        ],
    ];

//简单方法，这是个单点的处理，所以只处理一个起点的KEY即可。
    $a1 = [];       //顺查数组
    $a2 = [];       //逆查数组
    foreach($chepiao as $v) {
        $a1[$v['start']] = $v;
        $a2[$v['end']] = $v;
    }
    $num = 0;
    $sk = 'start';
    $ek = 'end';
    if(isset($a1[$start]) && isset($a2[$end])) {
    } else if (isset($a2[$start]) && isset($a1[$end])) {
        $a1 = $a2;
        $ek = 'start';
        $sk = 'end';
    } else {
        echo '起止站点无法查询' . PHP_EOL;
        exit;
    }
    $s1 = $start;
    $v = $a1[$s1];
    $sites = [];
    while(true) {
        $num += $v['money'];
        if($v[$ek] == $end) {
            break;
        }
        $v = $a1[$v[$ek]];
        $s1 = $v[$sk];
        $sites[] = $s1;
        if(count($sites)>count($a1)) {
            break;
        }
    }
    $sites[] = $end;
//    print_r($sites);
    echo '从《' . $start . '》到《' . $end . '》共' . count($sites) . '站，需要' . $num . '元' . PHP_EOL;
}

最后修改：4年前